x^2-4x-16.5=0

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Solution for x^2-4x-16.5=0 equation:



x^2-4x-16.5=0
a = 1; b = -4; c = -16.5;
Δ = b2-4ac
Δ = -42-4·1·(-16.5)
Δ = 82
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{82}}{2*1}=\frac{4-\sqrt{82}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{82}}{2*1}=\frac{4+\sqrt{82}}{2} $

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